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Question

Quantitative Aptitude Question on Inequalities

If 0 << p << I, which of the following has the least value?

A

1p2+1\frac{1}{p^2+1}

B

19\frac{1}{\sqrt 9}

C

1p2\frac{1}{p^2}

D

1(p+1)2\frac{1}{(p+1)^2}

Answer

1(p+1)2\frac{1}{(p+1)^2}

Explanation

Solution

A. 1p2+1.........11.0016\frac{1}{p^2+1}.........\frac{1}{1.0016}
D. 1(p+1)2=11.00162\frac{1}{(p+1)^2}=\frac{1}{1.0016^2}

Only A and D are <1<1 , and D has a larger denominator and same numerator, so D is the least.
The correct option is (D): 1(p+1)2\frac{1}{(p+1)^2}