QuestionReportMathematics Question on types of differential equationsIf ∫−0.150.15∣100x2−1∣dx=k3000,∫^{0.15}_{-0.15 }|100x^2-1|dx=\frac{k}{3000,}∫−0.150.15∣100x2−1∣dx=3000,k then k is equal to____.AnswerThe correct Answer is: 575
