Question

Identify X and Y in the following reaction

$BCl_{3} + NH_{4}Cl\underset{C_{6}H_{5}Cl}{\overset{\quad 140^{o}C\quad}{\rightarrow}}X\overset{\quad NaBH_{4}\quad}{\rightarrow}Y$

• A. $X = NaBO_{2},Y = B_{2}O_{3}$
• B. $X = Na_{2}B_{4}O_{7},Y = H_{3}BO_{3}$
• C. $X = BN,Y = \lbrack NH_{4}\rbrack^{+}\lbrack BCl_{4}\rbrack^{-}$
• D. $X = B_{3}N_{3}H_{3}Cl_{3},Y = B_{3}N_{3}H_{6}$

Answer 1

Answer: (D)

$X = B_{3}N_{3}H_{3}Cl_{3},Y = B_{3}N_{3}H_{6}$

Answer 2

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