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Question: Identify the valency of element X in the following compounds. (A) \(X{{H}_{3}}\) (B) \(XC{{l}_{5...

Identify the valency of element X in the following compounds.
(A) XH3X{{H}_{3}}
(B) XCl5XC{{l}_{5}}
(C) X2O3{{X}_{2}}{{O}_{3}}
(D) XO2X{{O}_{2}}

Explanation

Solution

Valency of Hydrogen atom is 1. Chlorine atom has valency of 1. The oxygen atom’s valency is 2. To get the formula of compound, the valency of constituent atoms is crisscrossed. The crisscrossed values are reduced to the smallest possible ratio.

Complete step by step solution:
a) XH3X{{H}_{3}}
Let the valency of X atom be aa.
We know that the formula of compound is written by crisscrossing the valencies. The valency of a Hydrogen atom is 1.
Therefore,
(XH a1 )\left( \begin{matrix} X & H \\\ a & 1 \\\ \end{matrix} \right)
So, the formula becomes XHaX{{H}_{a}}, comparing it with XH3X{{H}_{3}}
We get aa as 3 so the valency of X atom is 3 in XH3X{{H}_{3}}.
b) XCl5XC{{l}_{5}}
Let the valency of X atom be aa.
We know that the formula of compound is written by crisscrossing the valencies. The valency of Chlorine atoms is 1.
Therefore,
(XCl a1 )\left( \begin{matrix} X & Cl \\\ a & 1 \\\ \end{matrix} \right)
So, the formula becomes XClaXC{{l}_{a}}, comparing it with XCl5XC{{l}_{5}}
We get aa as 5 so the valency of X atom is 5 in XCl5XC{{l}_{5}}.
c) X2O3{{X}_{2}}{{O}_{3}}
Let the valency of X atom be aa.
We know that the formula of compound is written by crisscrossing the valencies. The valency of Oxygen is 2.
Therefore,
(XO a2 )\left( \begin{matrix} X & O \\\ a & 2 \\\ \end{matrix} \right)
So, the formula becomes X2Oa{{X}_{2}}{{O}_{a}}, comparing it with X2O3{{X}_{2}}{{O}_{3}}
We get aa as 3 so the valency of X atom is 3 in X2O3{{X}_{2}}{{O}_{3}}.
d) XO2X{{O}_{2}}
Let the valency of X atom be aa.
We know that the formula of compound is written by crisscrossing the valencies. The valency of Oxygen is 2.
Therefore,
(XO a2 )\left( \begin{matrix} X & O \\\ a & 2 \\\ \end{matrix} \right)
So, the formula becomes X2Oa{{X}_{2}}{{O}_{a}}, comparing it with XO2X{{O}_{2}}
We get the ratio as 2: aa = 1:2 which gives us a as 4.
We get aa as 4 so the valency of X atom is 4 in XO2X{{O}_{2}}.

Note: -Atoms having 1 valency are Sodium, Potassium, Silver and gold. Magnesium and Calcium have 2 as valency. Aluminium atom as 3 as valency. Fluorine atoms have 1 as valency.
- When a compound consists of metal and non-metal the symbol or name of metal is written first in the formula or name of the compound.