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Question: Identify the redox reaction taking place in a beaker. <img src="https://cdn.pureessence.tech/canvas...

Identify the redox reaction taking place in a beaker.

A

Zn(s)+Cu(aq)2+→Zn(aq)2++Cu(s)Zn_{(s)} + Cu_{(aq)}^{2 +} \rightarrow Zn_{(aq)}^{2 +} + Cu_{(s)}

B

Cu(s)+2Ag(aq)+→Cu(aq)2++2Ag(s)Cu_{(s)} + 2Ag_{(aq)}^{+} \rightarrow Cu_{(aq)}^{2 +} + 2Ag_{(s)}

C

Cu(s)+Zn(aq)2+→Zn(s)+Cu(aq)2+Cu_{(s)} + Zn_{(aq)}^{2 +} \rightarrow Zn_{(s)} + Cu_{(aq)}^{2 +}

D

2Ag(s)+Cu(aq)2+→2Ag(aq)++Cu(s)2Ag_{(s)} + Cu_{(aq)}^{2 +} \rightarrow 2Ag_{(aq)}^{+} + Cu_{(s)}

Answer

Cu(s)+2Ag(aq)+→Cu(aq)2++2Ag(s)Cu_{(s)} + 2Ag_{(aq)}^{+} \rightarrow Cu_{(aq)}^{2 +} + 2Ag_{(s)}

Explanation

Solution

: Since copper is more reactive than silver, it displaces Ag+Ag^{+}ions from its salt solution which get deposited on the copper rod.