Question

Identify the product/s in the following reaction. $3C{{H}_{3}}CH=C{{H}_{2}}\xrightarrow[{}]{B{{H}_{3}}}X\xrightarrow[{}]{{{H}_{2}}{{O}_{2}}/O{{H}^{-}}}$ $product/s+{{H}_{3}}B{{O}_{3}}$

• A. $C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH$
• B. $C{{H}_{3}}CHOHC{{H}_{3}}$
• C. $C{{H}_{3}}C{{H}_{2}}CHO$
• D. $C{{H}_{3}}C{{H}_{2}}OH+C{{H}_{3}}OH$

Answer 1

Answer: (A)

$C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH$

Answer 2

$3C{{H}_{3}}CH\equiv C{{H}_{2}}\xrightarrow[{}]{+B{{H}_{3}}}$ ${{(C{{H}_{3}}C{{H}_{2}}-C{{H}_{2}}-)}_{3}}B\xrightarrow[{}]{{{H}_{2}}{{O}_{2}}/O{{H}^{-}}}$ $3C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH+{{H}_{3}}B{{O}_{3}}$