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Question: Identify the product obtained when benzamide is treated with bromine and aqueous sodium hydroxide?...

Identify the product obtained when benzamide is treated with bromine and aqueous sodium hydroxide?

A

Aniline

B

Benzyl alcohol

C

Phenol

D

Bromobenzene

Answer

Aniline

Explanation

Solution

Benzamide reacts with bromine and aqueous NaOH via the Hofmann rearrangement. In this reaction, the amide group (–CONH₂) undergoes a rearrangement to form an amine (–NH₂) with the loss of the carbonyl carbon as CO₂. Thus, benzamide (C₆H₅CONH₂) is converted to aniline (C₆H₅NH₂).