Question

Identify the product (C) in the given reaction;

(1)

(2)

(3)

(4)

Answer 1

The starting reactant has a carbonyl group, and the name of the functional group is a ketone (acetophenone), with a phenyl group, and if observed the groups are nitrous acid (HONO), acetic anhydride, and the last step is hydrolysis.

Complete step-by-step answer: So, here we have the first reactant is acetophenone, which is reacting with${\text{NaN}}{{\text{O}}_{\text{2}}}$/ ${\text{HCl}}$, this group will give a nitrous acid (HONO), which will attack the acetophenone and form an oxime derivative. Following is the reaction observed in the formation of product ‘A’

${\text{NaN}}{{\text{O}}_{\text{2}}}{\text{ + HCl}} \to {\text{HN}}{{\text{O}}_{\text{2}}}$

${\text{Ph}} - \mathop {\mathop {\text{C}}\limits^{{\text{||}}} }\limits^{\text{O}} - {\text{CH}} = {\text{N}} - {\text{OH}}$ is the product (A) that is formed, now this oxime derivative will react with acetic anhydride and remove ${{\text{H}}_{\text{2}}}{\text{O}}$ molecules from the oxime derivative compound. The following reaction will take place:

Now, in the last step, the nitrile group will get hydrolyzed (${{\text{H}}_3}{{\text{O}}^ + }$) and form a carboxylic acid derivative:

Hence, the correct answer is option(3).

Note: : In the reaction of acetophenone with (HONO), there are two possible products of ‘A’, both have a similar molecular formula, 1st oxime derivative and the other with the tautomerization of oxime (${\text{Ph}} - \mathop {\mathop {\text{C}}\limits^{{\text{||}}} }\limits^{\text{O}} - {\text{C}}{{\text{H}}_{\text{2}}} - {\text{N}} = {\text{O}}$), but we have used the oxime derivative as in the next step of dehydration the oxime derivative will be more easily lose ${{\text{H}}_{\text{2}}}{\text{O}}$ molecules and form the corresponding product with a nitrile group.