Question

Identify the incorrect statement:
A. The $S-S-S$ bond angles in ${{S}_{8}}$ and ${{S}_{6}}$ rings are the same
B. Rhombic and monoclinic sulphur have ${{S}_{8}}$ molecules
C. ${{S}_{2}}$ is paramagnetic like oxygen
D. ${{S}_{8}}$ rings has a crown shape

Answer 1

Sulphur has puckered ${{S}_{8}}$​ rings with crown conformation, sulphur is also known as Engel's sulphur contain ​ ${{S}_{6}}$ rings arranged in a chair conformation.

Complete step by step answer:
->Option 1st: The $S-S-S$ bond points in the s8 and ${{S}_{6}}$ the ring are the equivalent. This announcement isn't right since the state of ${{S}_{8}}$ is like a crown while the state of ${{S}_{6}}$ is hexagonal.
->Option 2nd: Rhombic and monoclinic sulfur have ${{S}_{8}}$ particles: this announcement is likewise right.
->Option 3rd: ${{S}_{2}}$ paramagnetic like oxygen: we know, Oxygen is paramagnetic in nature in view of oxygen having two unpaired electrons in the valence shell. Likewise sulfur has a place with an oxygen family that is the reason sulfur, ${{S}_{2}}$ is also paramagnetic subsequently, it is right.
->Option 4th: ${{S}_{8}}$ ring has crown shape, no doubt it is additionally right proclamation. ${{S}_{8}}$ has crown shape.
The $S-S-S$ bond angles in the ${{S}_{8}}$ and ${{S}_{6}}$ rings are the same. The $S_6$ molecule has a chair-form hexagon ring with the same bond length as that in ${{S}_{8}}$ but with somewhat smaller bond angles i.e. bond lengths are same but bond angles are different.

**Hence, the correct option is A. The $S-S-S$ bond angles in ${{S}_{8}}$ and ${{S}_{6}}$ rings are the same

Note: **
The ${{S}_{8}}$ molecule has a zigzag shape (“crown”), which allows for $S-S-S$ angles of about ${{107}^{\circ }}$ quite close to the optimum and ${{S}_{6}}$, which indeed does exist, isn’t planar but has a “chair” configuration similar to cyclohexane.