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Question

Chemistry Question on Thermodynamics

Identify the equation in which change in enthalpy is equal to change in internal energy

A

2H2O2(I)2H2O(I)+O2(g)2H_{2}O_{2} (I) \to 2H_{2}O(I) +O_{2}(g)

B

C(s)+O2(g)CO2(g)C(s) +O_{2}(g) \to CO_{2}(g)

C

PCl5(g)PCl3(g)+Cl2(g)PCl_{5}(g) \to PCl_{3}(g) +Cl_{2}(g)

D

N2(g)+3H2(g)2NH3(g)N_{2}(g) + 3\,H_{2}(g) \to 2NH_{3}(g)

Answer

C(s)+O2(g)CO2(g)C(s) +O_{2}(g) \to CO_{2}(g)

Explanation

Solution

Relationship between change in enthalpy and change in intemal energy is given as: ΔH=ΔU+ΔngRT\Delta H=\Delta U+\Delta n_{g} RT In the given options, (a) 2H2O2(l)2H2O(l)+O2(g)2 H _{2} O _{2}(l) \to 2H _{2} O (l)+ O _{2}(g) Δng=1\Delta n_{g} = 1 ΔH=ΔU+RT\therefore \Delta H=\Delta U+RT (b) C(s)+O2(g)CO2(g)C ( s )+ O _{2}(g) \to CO _{2}(g) Δng=11=0 \Delta n_{ g }=1-1=0 ΔH=ΔU\therefore \Delta H=\Delta U (c) PCl5(g)PCl3(g)+Cl2(g)PCl _{5}(g) \to PCl _{3}(g)+ Cl _{2}(g) Δng=21=1\Delta \,n_{g}=2-1=1 ΔH=ΔU+RT\therefore \Delta H=\Delta U+RT (d) N2(g)+3H2(g)2NH3(g)N _{2}(g)+3 H _{2}(g) \to 2 NH _{3}(g) ΔngRT=23=1\Delta\, n_{g}RT=2-3=-1 ΔH=ΔURT\therefore \Delta H=\Delta U-RT Equation given in option (b) has enthalpy change equal to internal change