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Question

Chemistry Question on Oxidation Number

Identify the correct statement(s):

A

The oxidation number of Cr in CrO5CrO_{5} is + 6.

B

ΔH>ΔU\Delta H >\Delta U for the reaction N2O4(g)2NO2(g),N_{2}O_{4}\left(g\right)\rightarrow2NO_{2} \left(g\right),provided both gases behave ideally.

C

pH of 0.1N H2SO4H_{2}SO_{4} is less than that of 0.1N HCl at 25?C.

D

(RTF)\binom{RT}{F} =0.0591 volt at 25?C.

Answer

ΔH>ΔU\Delta H >\Delta U for the reaction N2O4(g)2NO2(g),N_{2}O_{4}\left(g\right)\rightarrow2NO_{2} \left(g\right),provided both gases behave ideally.

Explanation

Solution

(B)N2O4(g)2NO2(g),ΔH=ΔU+ΔngRT=ΔU+(21)RT=ΔU+RTN_{2}O_{4} \left(g\right) \to2NO_{2} \left(g\right), \Delta H =\Delta U +\Delta n_{g}RT =\Delta U +\left(2-1\right)RT =\Delta U+RT
H>ΔU\therefore\bigtriangleup H >\Delta U\because Reaction is endothermic
(C) For 0.1N H2SO4H_{2}SO_{4} solution, [H+]=0.1NpH=1\left[H^{+}\right]=0.1N\therefore pH=1
For 0.1NHCl solution,[H+]=0.1NpH=1\left[H^{+}\right]=0.1N\therefore pH=1 same
(D) is incorrect as RFF=\frac{RF}{F} = 8.314×29896500=0.0256V\frac{8.314\times298}{96500} =0.0256V