Solveeit Logo
Login

Question

Chemistry Question on Classification of elements & periodicity in properties

Identify the correct order of the size of the following.

A

Ca2+<K+<Ar<S2−<Cl−Ca^{2+} < K^+ < Ar < S^{2-} < Cl^{-}

B

Ca2+<K+<Ar<Cl−<S2−Ca^{2+} < K^+ < Ar < Cl^- < S^{2-}

C

Ar<Ca2+<K+<Cl−<S2−Ar < Ca^{2+} < K^+ < Cl^- < S^{2-}

D

Ca2+<Ar<K+<Cl−<S2−Ca^{2+} < Ar < K^+ < Cl^- < S^{2-}

Answer

Ca2+<K+<Ar<Cl−<S2−Ca^{2+} < K^+ < Ar < Cl^- < S^{2-}

Explanation

Solution

A cation has always the lesser ionic size than a metal atom due to loss of electrons and an anion has always the greater size than metal atom due to gain of electrons. So, the correct order of size is as
           Ca2+<K+<Ar<Cl−<S2−\, \, \, \, \, \, \, \, \, \, \, Ca^{2+} < K^+ < Ar < Cl^- < S^{2-}