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Question

Chemistry Question on coordination compounds

Identify the correct increasing order of crystal field stabilization energy value for the given complexes.

A

[Ir(NH3)6]3+<[Rh(NH3)6]3+<[Co(NH3)6]3+\left[Ir\left(NH_{3}\right)_{6}\right]^{3+} < \left[Rh\left(NH_{3}\right)_{6}\right]^{3+} < \left[Co\left(NH_{3}\right)_{6}\right]^{3+}

B

[Rh(NH3)6]3+<[Co(NH3)6]3+<[Ir(NH3)6]3+\left[Rh\left(NH_{3}\right)_{6}\right]^{3+} < \left[Co\left(NH_{3}\right)_{6}\right]^{3+} < \left[Ir\left(NH_{3}\right)_{6}\right]^{3+}

C

[Co(NH3)6]3+<[Ir(NH3)6]3+<[Rh(NH3)6]3+\left[Co\left(NH_{3}\right)_{6}\right]^{3+} < \left[Ir\left(NH_{3}\right)_{6}\right]^{3+} < \left[Rh\left(NH_{3}\right)_{6}\right]^{3+}

D

[Co(NH3)6]3+<[Rh(NH3)6]3+<[Ir(NH3)6]3+\left[Co\left(NH_{3}\right)_{6}\right]^{3+} < \left[Rh\left(NH_{3}\right)_{6}\right]^{3+}< \left[Ir\left(NH_{3}\right)_{6}\right]^{3+}

Answer

[Co(NH3)6]3+<[Rh(NH3)6]3+<[Ir(NH3)6]3+\left[Co\left(NH_{3}\right)_{6}\right]^{3+} < \left[Rh\left(NH_{3}\right)_{6}\right]^{3+}< \left[Ir\left(NH_{3}\right)_{6}\right]^{3+}

Explanation

Solution

The elements in the 2nd2^{nd} and 3rd3^{rd} transition series (the 4d4d and 5d5d elements) have large splitting than those in 3d3d series. So, the order of CFSECFSE is
[Co(NH3)6]3+<[Rh(NH3)6]3+<[Ir(NH3)6]3+[Co(NH_{3})_{6}]^{3+} < \, [Rh(NH_{3})_{6}]^{3+} < \, [Ir(NH_{3})_{6}]^{3+}