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Question: Identify CORRECT statement for following reaction. $H_2O_{2(aq)}+CIO_{4(aq)}^-\longrightarrow CIO_{...

Identify CORRECT statement for following reaction.

H2O2(aq)+CIO4(aq)−⟶CIO2(aq)−+O2(g)H_2O_{2(aq)}+CIO_{4(aq)}^-\longrightarrow CIO_{2(aq)}^- + O_{2(g)}

A

Oxidation state of Cl decreases from +7 to +4

B

Oxidation state of oxygen on product side is -1 and -2 respectively

C

Oxidation state of oxygen on reactant side is -1 and -2 respectively.

D

Oxidation state of Cl is +3 on reactant side and +1 on product side.

Answer

Option (C) states that the oxidation state of oxygen on the reactant side is -1 (in H2O2H_2O_2) and -2 (in ClO4−ClO_4^-), which is correct.

Explanation

Solution

  1. In ClO4−ClO_4^-: Let oxidation state of Cl = xx. Then,

    x+4(−2)=−1  ⟹  x−8=−1  ⟹  x=+7.x + 4(-2) = -1 \implies x - 8 = -1 \implies x = +7.

  2. In ClO2−ClO_2^-: Let oxidation state of Cl = yy. Then,

    y+2(−2)=−1  ⟹  y−4=−1  ⟹  y=+3.y + 2(-2) = -1 \implies y - 4 = -1 \implies y = +3.

    Thus, chlorine goes from +7 to +3.

  3. For oxygen:

    • In H2O2H_2O_2 (hydrogen peroxide), oxygen has oxidation state -1.
    • In ClO4−ClO_4^-, oxygen has oxidation state -2.
    • In ClO2−ClO_2^-, oxygen again is -2.
    • In O2O_2, oxygen is 0.

    Therefore, only option (C) is correct.