Question

Identify Bronsted-Lowry acids in the reaction given. $\underset{(A)}{\mathop{{{[Al{{({{H}_{2}}O)}_{2}}]}^{3+}}}}\,+\underset{(B)}{\mathop{HCO_{3}^{-}}}\,\underset{(C)}{\mathop{{{[Al{{({{H}_{2}}O)}_{5}}(O{{H}^{-}})]}^{2+}}}}\,$ $\underset{(D)}{\mathop{+{{H}_{2}}C{{O}_{3}}}}\,$ The correct answer is

• A. ,
• B. (B,)
• C. ,
• D. ,

Answer 1

Answer: (D)

,

Answer 2

According to Bronsted-Lowry, acids are the substance which can donate a proton while bases are the substance which can accept a proton. A base after gaining a proton $({{H}^{+}})$ gives conjugated acid. $\underset{acid}{\mathop{{{[Al{{({{H}_{2}}O)}_{6}}]}^{3+}}}}\,+\underset{\begin{smallmatrix} (B) \\\ base \end{smallmatrix}}{\mathop{HCO_{3}^{-}}}\,\rightleftharpoons$ $\underset{\begin{smallmatrix} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C \\\ conjugate\,base \end{smallmatrix}}{\mathop{{{[Al{{({{H}_{2}}O)}_{5}}(O{{H}^{-}})]}^{2+}}}}\,+\underset{\begin{smallmatrix} \,\,\,\,\,\,\,\,\,\,\,\,\,(D) \\\ conjugate\,acid \end{smallmatrix}}{\mathop{{{H}_{2}}C{{O}_{3}}}}\,$ Hence, in the above reaction A and D are the acids.