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Question: Identify alkene and alkyne from the following. (i) \({{C}_{2}}{{H}_{6}}\) (ii) \({{C}_{3}}{{H}_...

Identify alkene and alkyne from the following.
(i) C2H6{{C}_{2}}{{H}_{6}}
(ii) C3H4{{C}_{3}}{{H}_{4}}
(iii) C3H6{{C}_{3}}{{H}_{6}}
(iv) C3H8{{C}_{3}}{{H}_{8}}

Explanation

Solution

Both alkenes and alkynes are the categories of unsaturated hydrocarbons i.e. they have less hydrogen atoms making them unsaturated and different from the alkane group (saturated hydrocarbons).

Complete step-by-step answer: Let us study the basics of three categories of hydrocarbons;
Alkane-
The saturated hydrocarbons that would contain single bonds and will have general formula as CnH2n+2{{C}_{n}}{{H}_{2n+2}} .
Alkene-
The unsaturated hydrocarbons that would at least contain one double bond and will have general formula as CnH2n{{C}_{n}}{{H}_{2n}} .
Alkyne-
The unsaturated hydrocarbons that would at least contain one triple bond and will have general formula as CnH2n2{{C}_{n}}{{H}_{2n-2}} .
Now, according to the given definitions we can classify the above given molecules as follows;
(i) C2H6{{C}_{2}}{{H}_{6}} - This molecule resembles the general formula as CnH2n+2{{C}_{n}}{{H}_{2n+2}} and thus it is an alkane.
(ii) C3H4{{C}_{3}}{{H}_{4}} - This molecule resembles the general formula as CnH2n2{{C}_{n}}{{H}_{2n-2}} and thus it is an alkyne.
(iii) C3H6{{C}_{3}}{{H}_{6}} - This molecule resembles the general formula as CnH2n{{C}_{n}}{{H}_{2n}} and thus it is an alkene.
(iv) C3H8{{C}_{3}}{{H}_{8}} - This molecule resembles the general formula as CnH2n+2{{C}_{n}}{{H}_{2n+2}} and thus it is an alkane.
Thus, C3H6{{C}_{3}}{{H}_{6}}is the alkene and C3H4{{C}_{3}}{{H}_{4}}is the alkyne from all of the above-mentioned molecules.

Note: Do not that the molecular formula alone can be used to determining and identifying the actual category of a compound.
For example, C6H12{{C}_{6}}{{H}_{12}} can be said unsaturated hydrocarbon (alkene) according to the general formula as CnH2n{{C}_{n}}{{H}_{2n}} and also as the saturated cyclic hydrocarbon.