Question

Identify A, B, C, D, E, R and R’

Answer 1

Hint: Alkyl halide and cyclohexyl halide reacts with magnesium in presence of dry ether to give ${\text{RMgX}}$ that is known as Grignard reagent. In the presence of ${\text{Na/ether}}$ , two alkanes or cycloalkanes join, the reaction is known as Wurtz fittig reaction.

Step by step answer:

All the reactants and products can be identified by using Grignard reagent formation reactions and Wurtz fittig reaction.

The reaction of bromocyclo hexane with magnesium in presence of dry ether is use to produce

${\text{ArMgX}}$that is known as grignard reagent. The grignard reagent is used to generate a

nucleophile ${\text{A}}{{\text{r}}^ - }$.

The reactions are as follows:

So, product A is cyclohexyl magnesium bromide and product B is cyclohexane.

The second reactions are as follows:

The $1 -$ bromopropane reacts with magnesium in presence of dry ether to give propane magnesium

bromide which generates propane nucleophiles. The hydrogen shifting generates the ${2^ \circ

}$nucleophile which attacks on deuterated water to give deuterated propane.

So, the R is The $1 -$ bromopropane $$\left(

{{\text{C}}{{\text{H}}{\text{3}}}{\text{C}}{{\text{H}}{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\

text{Br}}} \right)$$and C is propane magnesium bromide.

$\left( {{\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{MgBr}}} \right)$.

The third reactions are as follows:

$2 -$ halide $2 -$ methylpropane reacts with magnesium in presence of dry ether to give $2 -$

halide magnesium $2 -$ methyl propane which generate $2 -$ methylpropane nucleophilic that

reacts with water to give $2 -$ methyl propane.

So, the product D is $2 -$ halide magnesium $2 -$ methyl propane, the product E is$2 -$ methyl

Propane and the in reactant is $2 -$ methyl propane.

Therefore, A is cyclohexyl magnesium bromide $$\left(

{{{\text{C}}{\text{6}}}{{\text{H}}{\text{5}}}{\text{MgBr}}} \right)$$, B is cyclohexane

, R is $1 -$ bromopropane $$\left(

{{\text{C}}{{\text{H}}{\text{3}}}{\text{C}}{{\text{H}}{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\

text{Br}}} \right)$and C is propane magnesium bromide$\left(

{{\text{C}}{{\text{H}}{\text{3}}}{\text{C}}{{\text{H}}{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\

text{MgBr}}} \right)$$, D is

$2 -$ halide magnesium $2 -$ methyl propane$$\left(

{{\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\left( {{\text{C}}{{\text{H}}_3}}

\right)}_2}{\text{MgX}}} \right)$$, E is $2 -$methyl propane

\right)}_2}{\text{H}}} \right)$$and the is $2 - $ halide $2 - $methyl propane $$\left( {{\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\left( {{\text{C}}{{\text{H}}_3}} \right)}_2}{\text{X}}} \right)$$. Note: Grignard reagent is used for generation of the nucleophile. Water is used for hydrolysis. The reagent used for the preparation of Grignard reagent is dry ether whereas the reagent used for Wurtz fittig reaction is ${\text{Na/ether}}$