Question
Question: Ideal monatomic gas is taken through a process \(dQ=2dU\). What will be the molar heat capacity for ...
Ideal monatomic gas is taken through a process dQ=2dU. What will be the molar heat capacity for the process? (where dQ is heat supplied and dU is change in internal energy)
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Solution
The change in heat energy at the constant pressure is given as the product of number of moles, specific heat at constant volume and the change in temperature. The change in internal energy is given as the product of the number of moles, specific heat at constant pressure and the change in temperature. Equate both the equations according to the relation and find the answer.
Complete step by step answer:
the change in heat energy at the constant pressure is given as
dQ=nCpdT
Where Cp be the specific heat at constant pressure, n be the number of moles and dT be the change in temperature.
The change in internal energy at constant volume is given as,
dU=nCvdT
Where Cv be the specific heat at constant volume.
As per the question, the change in heat energy is equal to the twice of the change in internal energy.
That is,
dQ=2dU
Substituting the equations in it will give,
nCpdT=2nCvdT
We can cancel the common terms on both the sides. Therefore we can write that,
Cp=2Cv
The specific heat at constant volume is given by the formula,
Cv=γ−1R
Where γbe the Poisson’s ratio.
Substituting the value in the equation will give,
Cp=2γ−1R
For monoatomic gases, the Poisson’s ratio will be,
γ=35
Substituting the value in the equation will give,