Question
Question: Ice point and steam point on a particular scale reads 10<sup>0</sup> and 80<sup>0</sup> respectively...
Ice point and steam point on a particular scale reads 100 and 800 respectively. The temperature on 0F scale when temperature on new scale is 450 is –
A
500 F
B
1120F
C
1220F
D
1380F
Answer
1220F
Explanation
Solution
Relation between the two scales
80–10t–10 = 180F–32
F = 718 (t – 10) + 32