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Question: (i) What mass of oxygen is required to react completely with\[24g\] of \[C{H_4}\] in the following r...

(i) What mass of oxygen is required to react completely with24g24g of CH4C{H_4} in the following reaction?
CH4(g)+2O2(g)CO2(g)+2H2O(L)C{H_4}_{\left( g \right)} + 2{O_2}_{\left( g \right)} \to C{O_2}_{\left( g \right)} + 2{H_2}{O_{\left( L \right)}}
(ii) How much mass of CH4C{H_4} would react with 96g96g of oxygen?

Explanation

Solution

Here one mole of methane is reacted with two moles of oxygen and one moles of carbon dioxide and two moles of water molecules. Methane is a chemical compound having the chemical formula, CH4C{H_4} with molecular mass 16g/mol16g/mol. Here the carbon is bonded with four hydrogen atoms by a single bond. The methane is the simplest alkane and it is used to prepare the chemicals and it is also used as a constituent of the fuel.

Complete answer:
(i) From the given reaction, we can say that one mole of methane requires two mol of oxygen to produce one mole of carbon dioxide and two moles of water molecules.
Molecular weight of methane=16g = 16g
Number of moles of methane=givenmassmolarmass = \dfrac{{given mass}}{{molar mass}}
Given mass is equal to 24g24g. Hence,
numberofmoles=2416=1.5molnumber of moles = \dfrac{{24}}{{16}} = 1.5mol
According to the chemical reaction, one mole of carbon dioxide requires two moles of oxygen. Hence,
The mass of oxygen is required to react completely with 24g24g of C{H_4}$$$$ = 2 \times 1.5
=3mol= 3\,mol
3mole=16×3=48g3\,mole = 16 \times 3 = 48g
Therefore, 48g48g of oxygen is required to react completely with 24g24g of CH4C{H_4} is equal to 48g48g.
(ii) One mole of methane reacts with two moles of oxygen.
Number of moles=givenmassmolarmass = \dfrac{{given mass}}{{molar mass}}
Given mass is equal to 96g96g and molar mass of oxygen molecules is equal to32g32g. Hence, one mole of oxygen requires 12\dfrac{1}{2} moles of methane. Which means, 32g32g of oxygen requires 16g16g of methane. Therefore,
Mass of CH4C{H_4} would react with 96g96g of oxygen=1632×96 = \dfrac{{16}}{{32}} \times 96
=48gofCH4= 48gofC{H_4}
Mass of CH4C{H_4} would react with 96g96g of oxygen is 48g48g.

Note:
We need to know that when the methane is reacted with oxygen there is a formation of carbon dioxide and water. The number of moles can be found by dividing given mass with molecular mass. The molecular weight is equal to the sum of atomic mass of every atom which is present in a compound or the molecule. And the molecular weight is another term of molar mass which is used for the molecular compounds, and it will not depend on the size of the sample.