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Question

Chemistry Question on Equilibrium

Hydroxyl ion concentration of 1M HCl1M\, HCl is

A

1×10−12mol dm−31 \times 10^{-12}mol \,dm^{-3}

B

1×10−13mol dm−31\times 10^{-13}mol\, dm^{-3}

C

1×10−13mol dm−31 \times 10^{-13} mol \, dm^{-3}

D

1×101mol dm−31 \times 10^1 mol \, dm^{-3}

Answer

1×10−12mol dm−31 \times 10^{-12}mol \,dm^{-3}

Explanation

Solution

[H+][OH−]=10−14\left[H^{+}\right] \left[OH^{-}\right]=10^{-14}
[10−2][OH−]=10−14\left[10^{-2}\right]\left[OH^{-}\right] = 10^{-14}
[OH−]=10−1410−2\left[OH^{-}\right] = \frac{10^{-14}}{10^{-2}}
=10−12 mol dm3=10^{-12} \,mol \,dm^{3}