Question

Hydrolysis of $XeF_4$ and $XeF_6$ with water gives

• A. $XeOF_4$
• B. $XeO_2F_2$
• C. $XeO_3$
• D. $XeOF_2$

Answer 1

Answer: (C)

$XeO_3$

Answer 2

Hydrolysis of $XeF_4$ and $XeF_6$ with water gives various products but the common product is $XeO_3$, which is an explosive.
$6XeF_4 + 12H_2O {->} 2XeO_3 + 24HF$
$+ 4Xe + 3O_2$
$XeF_6 + 3H_2O {->} XeO_3 + 6HF$.