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Question

Physics Question on kinetic theory

Hydrogen is at temperature TT and helium is at temperature 2T2T. The internal energy of both gases is the same. The ratio of number of moles of hydrogen and helium gases is

A

65\frac{6}{5}

B

56\frac{5}{6}

C

32\frac{3}{2}

D

23\frac{2}{3}

Answer

65\frac{6}{5}

Explanation

Solution

Internal energy of a gas, U=nCVTU = nC_VT where nn is the number of the moles of a gas and CvC_v is the molar specific heat at constant volume and TT is the temperature of the gas. As hydrogen is a diatomic gas, (CV)H2=52R\therefore\left(C_{V}\right)_{H_2} = \frac{5}{2}R As helium is a monatomic gas, (CV)He=32R\therefore\left(C_{V}\right)_{He} = \frac{3}{2}R According to the question UH2=UHeU_{H_2} = U_{He} nH2×(CV)H2×TH2\Rightarrow n_{H_2} \times\left(C_{V}\right)_{H_2} \times T_{H_2} =nHe×(CV)He×THe = n_{He}\times\left(C_{V}\right)_{He} \times T_{He} nH2×52R×T\therefore n_{H_2} \times\frac{5}{2}R \times T =nHe×32R×2T= n_{He} \times\frac{3}{2}R \times 2T nH2nHe=65 \frac{n_{H_2}}{n_{He}} = \frac{6}{5}