Question

Hydrogen gas is prepared in the laboratory by reacting dilute $HCl$ with granulated zinc. Following reaction takes place : $Zn+2HCl \to Zn Cl_{2} +H_{2}$ What would be the volume of hydrogen gas liberated at $STP$ when $32.65 \,g$ of zinc reacts with $HCl$?

• A. $10.03\,L$
• B. $11.35\,L$
• C. $11.57\,L$
• D. $9.53\,L$

Answer 1

Answer: (B)

$11.35\,L$

Answer 2

\underset{\text{65.3,g}}{ {Zn}} $+2HCl$ ${->}$ $ZnCl_{2}$+\underset{\text{22.7,L }}{ {H2}} According to the equation, $65.3\, g$ of $Zn$ liberates $= 22.7\, L$ of $H_{2}$ $32.65\, g$ of $Zn$ will liberate $= \frac {22.7}{65.3} \times32.65 = 11.35\,L$