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Question: Hydrogen and oxygen combine in the ratio of \[1:8\] by mass to form water. What mass of oxygen gas w...

Hydrogen and oxygen combine in the ratio of 1:81:8 by mass to form water. What mass of oxygen gas would be required to react completely with 3g3g of hydrogen gas?

Explanation

Solution

Here 1g1gof hydrogen is completely reacting with 88grams of oxygen. Because, the hydrogen and oxygen are combining in the ratio, 1:81:8. And by the combining of hydrogen and oxygen, there is a formation of water. Hence, by using the ratio, we can calculate the required amount of oxygen gas to react completely with 3g3gof hydrogen gas.

Complete answer:
According to the law of constant proportions, the elements are present in a definite ratio by mass. Here, 1g1gof hydrogen is completely reacting with 88grams of oxygen. Because, the hydrogen and oxygen are combining in the ratio, 1:81:8. And by the combining of hydrogen and oxygen, there is a formation of water.
Here, 1g1gof hydrogen react with 88grams oxygen
Hence, mass of oxygen gas would be required to react completely with 3g3gof hydrogen gas is equal to, 3×8=24g3 \times 8 = 24g.
Therefore, mass of oxygen gas would be required to react completely with 3g3gof hydrogen gas is equal to24g24g. Thus, we can say that, according to the law of constant proportions, the elements are present in a definite ratio by mass.

Note:
We have to know that the mass of oxygen gas would be required to react completely with 3g3g of hydrogen gas is equal to, 24g24g. According to the law of constant proportions, the chemical compounds are made up of elements and it is present in a fixed ratio by mass. There is no matter in the source. Water is a main example for this law, because it always contains a fixed mass ratio.