Solveeit Logo

Question

Question: Hybridization of carbon atom in \({\rm{C}}{{\rm{H}}_{\rm{3}}}^ + \) is: A. \({\rm{sp}}\) B. \({\...

Hybridization of carbon atom in CH3+{\rm{C}}{{\rm{H}}_{\rm{3}}}^ + is:
A. sp{\rm{sp}}
B. sp2{\rm{s}}{{\rm{p}}^{\rm{2}}}
C. sp3{\rm{s}}{{\rm{p}}^{\rm{3}}}
D. sp3d{\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{d}}

Explanation

Solution

We know that hybridization is the process in which two or more than two orbitals overlap and generate a bond between them. Usually, these bonds may be single bond, double bond and the triple bond.

Complete step by step answer:
The main orbitals which participated in the overlapping of electrons are s,  p,  d{\rm{s,}}\;{\rm{p,}}\;{\rm{d}} and f{\rm{f}}. With the help of these orbitals, we can identify the hybridization of any element or molecules. The main hybridization are sp,  sp2,  sp3,  sp3d{\rm{sp,}}\;{\rm{s}}{{\rm{p}}^{\rm{2}}}{\rm{,}}\;{\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{,}}\;{\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{d}} and sp3d2{\rm{s}}{{\rm{p}}^{\rm{3}}}{{\rm{d}}^{\rm{2}}}. All the hybridizations have different representations for the structural geometry.
As we all know, the molecule CH3+{\rm{C}}{{\rm{H}}_{\rm{3}}}^ + has three pairs of electrons nearby the carbon atom. The structural geometry of tCH3+{\rm{C}}{{\rm{H}}_{\rm{3}}}^ + is trigonal planar. The total hybrid orbitals of CH3+{\rm{C}}{{\rm{H}}_{\rm{3}}}^ + can be calculated is shown below.
Total  hybrid  orbitals=Number  of  bonds+Number  of  lone  pair  of  electrons{\rm{Total}}\;{\rm{hybrid}}\;{\rm{orbitals}} = {\rm{Number}}\;{\rm{of}}\;{\rm{bonds}} + {\rm{Number}}\;{\rm{of}}\;{\rm{lone}}\;{\rm{pair}}\;{\rm{of}}\;{\rm{electrons}}
So, the number of bond of carbon in CH3+{\rm{C}}{{\rm{H}}_{\rm{3}}}^ + molecule is three and the number of lone pair of electrons is zero.
Substitute all the respective values in the above mathematical equation.
Total  hybrid  orbitals=3+0 =3\begin{array}{c} {\rm{Total}}\;{\rm{hybrid}}\;{\rm{orbitals}} = {\rm{3}} + {\rm{0}}\\\ = {\rm{3}} \end{array}
Thus, we get three total hybrid orbitals which means it has one s{\rm{s}} orbital and two p{\rm{p}} orbitals. The carbon is one of the central atoms in it. So, the hybridization of carbon in CH3+{\rm{C}}{{\rm{H}}_{\rm{3}}}^ + molecule is sp2{\rm{s}}{{\rm{p}}^{\rm{2}}}

Hence, the correct answer for this question is B.

Note:
Nowadays, the hybridization I used for many research purposes in the branch of biochemical biology. The hybridization can generally be affected by the increasing or decreasing of temperature.