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Question

Chemistry Question on Equilibrium

HX is a weak acid ( Ka=10−5K_a = 10^{ - 5} ).lt forms a salt Na (0.1M) on reacting with caustic soda. The degree of hydrolysis of Na X is

A

0.01%

B

0.000001

C

0.001

D

0.005

Answer

0.01%

Explanation

Solution

Kh (X−)=KwKa=10−1410−5=10−9K_h \, ( X^ - ) = \frac{ K_w }{ K_a } = \frac{ 10^{ - 1 4 }}{ 10^{ - 5 }} = 10^{ - 9 }

α=KhC=10−90.10=10−4\alpha = \sqrt{ \frac{ K_h }{ C } } = \sqrt{ \frac{ 10^{ - 9 } }{ 0.10 } } = 10^{ - 4 }

% hydrolysis = 100 α\alpha =0.01