Question

The value of F so as to keep the smooth wedge stationary, when it is loaded with a block of mass M, which is connected with a light inextensible string, will be

• A. (A) Mg sin 2θ
• B. (B) Mg/2 sin 2θ
• C. (C) Mg sin θ
• D. (D) Mg cos θ

Answer 1

Answer: (B)

(B) Mg/2 sin 2θ

Answer 2

Explanation:
From the free body diagram of block,N=Mgcos⁡θFrom the free body diagram of wedge, for the horizontal direction, we haveF=Nsin⁡θHence, F=Mgcos⁡θsin⁡θorF=Mg2sin⁡2θ