Question

• A.
• B.
• C.
• D.

Answer 1

Answer: (C)

Answer 2

Reaction of $C_6H_5Br + CH_3Br$ with $\text{NaOH (alc.)}$ to Form B:

In the first step, the reaction of bromobenzene ($C_6H_5Br$) with methyl bromide ($CH_3Br$) in the presence of alcoholic NaOH undergoes a nucleophilic substitution to form B, which is ortho-bromophenol.

Reaction of B with $\text{HBr (ether)}$ to Form C:

In the second step, treating ortho-bromophenol with $\text{HBr}$ in ether leads to the formation of C, which is para-bromophenol.

Identifying the Relationship Between A and C:

Compound A (bromobenzene) and compound C (para-bromophenol) are position isomers because they differ in the position of the bromine and hydroxyl groups on the benzene ring.

Conclusion:

The structures of B and C are as shown in Option (3), and A and C are position isomers.