Question

As shown in the figure, a sector of 30° is removed from a circular disc of mass M and radius R. The moment of inertia of the remaining portion of disc about an axis passing through the centre and perpendicular to plane of disc is

• A. $\frac{5}{12}MR^2$
• B. $\frac{17}{2}MR^2$
• C. $\frac{11}{24}MR^2$
• D. $\frac{1}{6}MR^2$

Answer 1

Answer: (C)

$\frac{11}{24}MR^2$

Answer 2

The correct option is (C): $\frac{11}{24}MR^2$