Question

Calculate mass of Tollen’s Reagent Required?

• A. 18.70 kg
• B. 37.40 kg
• C. 9.35 kg
• D. 55.10 kg

Answer 1

Answer: (A)

18.70 kg

Answer 2

The correct answer is option (A) : 18.70 kg

The balanced equation is :

No. of moles of NH3 formed = $\frac{4\times 10^3}{17}$

$\therefore$ No. of moles of Tollen’s Reagent consumed = $\frac{4\times 10^3}{17}$

So, mass of Tollen’s Reagent = $\frac{4\times 10^3}{17}\times159$

= 18.70 kg