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Question: How would you rearrange the Henderson-Hasselbalch equation to find out \([a/ha]\) from \(pH = pKa + ...

How would you rearrange the Henderson-Hasselbalch equation to find out [a/ha][a/ha] from pH=pKa+log[a/ha]pH = pKa + \log [a/ha]?

Explanation

Solution

The Henderson-Hasselbalch equation is a mathematical equation which connects the pH of the solution and the pKap{K_a} which is equal to the logKa- \log {K_a}. The Ka{K_a} is the acid dissociation constant of weak acid and its conjugate base.

Complete step by step answer:
The equation which relates the pH of an aqueous solution of an acid to the acid dissociation constant of the acid is described as the Henderson-Hasselbalch equation.
The equation is given as shown below.
pH=pKa+log([Conjugate  base][weak  acid])pH = p{K_a} + \log \left( {\dfrac{{[Conjugate\;base]}}{{[weak\;acid]}}} \right)
The pKap{K_a} value is equal to the negative logarithm of acid dissociation constant of the weak acid. It measures the strength of the acid's solution. The weak acid has pKap{K_a} value ranging from 2-12 in water.
It is given as shown below.
pKa=log[Ka]p{K_a} = - \log \left[ {{K_a}} \right]
Where,
Ka{K_a} is the acid dissociation constant of the weak acid.
The reaction of the weak acid-conjugate base buffer is shown below.
HA(aq)+H3O(l)H3O+(aq)+A(aq)HA(aq) + {H_3}O(l) \rightleftarrows {H_3}{O^ + }(aq) + {A^ - }(aq)
The pH of the solution is given as shown below.
pH=pKa+log([A][HA])pH = p{K_a} + \log \left( {\dfrac{{[{A^ - }]}}{{[HA]}}} \right)
Now, we need to determine the ratio which exists between the concentration of the conjugate base, A{A^ - } and the concentration of the weak acid HA, add log on one side of the equation.
log([A][HA])=pHpKa\log \left( {\dfrac{{[{A^ - }]}}{{[HA]}}} \right) = pH - p{K_a}
If x is equal to y,
10x=10y{10^x} = {10^y}
The above equation is equivalent to
10log([A][HA])=10pHpKa{10^{\log \left( {\dfrac{{[{A^ - }]}}{{[HA]}}} \right)}} = {10^{pH - p{K_a}}}
As we know,
10log10(x)=x{10^{\log 10(x)}} = x
We get,
[A][HA]=10pHpKa\dfrac{{[{A^ - }]}}{{[HA]}} = {10^{pH - p{K_a}}}

Note:
The Henderson-Hasselbalch equation is useful for determining the pH of the buffer solution and also determining the equilibrium pH in an acid-base reaction. The equation can also be used to determine the amount of acid and conjugate base used to prepare the buffer solution of a particular pH.