Question

How would you predict the boiling point of a 0.200 m solution of potassium iodide in water?

Answer 1

Boiling point is the temperature at which the pressure applied by the surroundings upon a fluid is risen to by the pressure applied by the vapor of the fluid; under this condition, expansion of heat brings about the change of the fluid into its vapor without raising the temperature.

Complete step-by-step answer: To anticipate the adjustment in the boiling point of a solution from the original boiling point, we can utilize the equation:
$\Delta {T_b} = i.m.{K_b}$
Where, $\Delta {T_b}$ $=$change in boiling point of the solution in $^\circ C$
$i$ $=$Van’t Hoff factor
$m$ $=$Molality of the solution
${K_b}$ $=$Molal boiling point constant of the solvent
So, if we put all the values in the above equation we will get,
$\Delta {T_b} = 2 \times 0.200m \times 0.512\dfrac{{^\circ C}}{m} = 0.205^\circ C$
The Van't Hoff factor offers an understanding of the impact of solutes on the colligative properties of solutions. It is signified by the symbol 'i'. The Van't Hoff factor can be characterized as the proportion of the concentration of particles framed when a substance is disintegrated to the concentration of the substance by mass.

Note: The degree to which a substance associates or separates in a solution is portrayed by the Van't Hoff factor. For instance, when a non-electrolytic substance is dissolved in water, the estimation of i is for the normal one. In any case, when an ionic compound structures a solution in water, the estimation of i is equivalent to the total number of particles present in one formula unit of the substance.