Question

How will you separate a solution (miscible) of benzene + $CHC{{l}_{3}}$ ?
A. Sublimation
B. Filtration
C. Distillation
D. Crystallisation

Answer 1

As we know that benzene and chloroform ($CHC{{l}_{3}}$) are having different boiling and melting points. We can say that the differences in these properties can be used to separate the mixture of benzene + $CHC{{l}_{3}}$ .

Complete Solution :
- As we know that distillation is a process of separating the constituents of a liquid by boiling and condensation.
- We will do the process of particularly fractional distillation because as we know that boiling point of benzene is ${{80}^{\circ }}C$ and that of chloroform is ${{61.2}^{\circ }}C$. We mainly use Fractional distillation because it basically includes repeated distillation and condensation, in a fractionating column.
- It is found that due to condensation and distillation at every point, the liquid falling back into the flask is found to be rich in less volatile components. And the vapours that are rising up become rich in more volatile components.
Therefore, we can say that low boiling liquid will distil first, whereas the high boiling liquid will distil afterward.
Hence, we can conclude that the correct option is (c), that is we will you separate a solution (miscible) of benzene + $CHC{{l}_{3}}$ by method of Distillation
So, the correct answer is “Option C”.

Note: - We should note here that we can use the distillation process only if the boiling points of the components of the mixture are different.
- We can separate the liquid and solid mixtures that have different boiling points by distillation process.