Question
Question: How to use Rolle’s theorem for \[f\left( x \right)=\left( \dfrac{{{x}^{3}}}{3} \...
How to use Rolle’s theorem for f(x)=(3x3)−3x on the interval [−3,3]?
Solution
In this problem, we have to use Rolle’s theorem for the given function within the given interval. We know that Rolle’s theorem states that if a continuous differentiable function f(x) satisfies f(a)=f(b)=0,a<b, then there is a point x∈(a,b) where f′(x) vanishes. We have to see whether the conditions in the Rolle’s theorem are satisfied as we use Rolle’s theorem for the given function.
Complete step-by-step solution:
We know that the given function is,
f(x)=(3x3)−3x on the interval [−3,3].
We can now see that,
⇒f(x) is a continuous function.
⇒f(−3)=0=f(3)
When we apply the given values of a and b in f(x), we get 0.
Thus, the conditions of Rolle’s theorem are satisfied with a = -3 and b = 3 and so there is a x∈(a,b)which satisfies f′(x)=0.
We can now find f′(x)by differentiating f(x).
⇒f′(x)=x2−3
We can now substitute ±3 in f′(x), to get the condition to be satisfied.