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Question: How‌ ‌to‌ ‌use‌ ‌Rolle’s‌ ‌theorem‌ ‌for‌ ‌\[f\left(‌ ‌x‌ ‌\right)=\left(‌ ‌\dfrac{{{x}^{3}}}{3}‌ ‌\...

How‌ ‌to‌ ‌use‌ ‌Rolle’s‌ ‌theorem‌ ‌for‌ ‌f(‌‌x‌‌)=(‌‌x33‌‌)3xf\left(‌ ‌x‌ ‌\right)=\left(‌ ‌\dfrac{{{x}^{3}}}{3}‌ ‌\right)-3x‌ ‌on‌ ‌the interval [3,3]\left[ -3,3 \right]?

Explanation

Solution

In this problem, we have to use Rolle’s theorem for the given function within the given interval. We know that Rolle’s theorem states that if a continuous differentiable function f(x)f\left( x \right) satisfies f(a)=f(b)=0,a<bf\left( a \right)=f\left( b \right)=0,a< b, then there is a point x(a,b)x\in \left( a,b \right) where f(x)f'\left( x \right) vanishes. We have to see whether the conditions in the Rolle’s theorem are satisfied as we use Rolle’s theorem for the given function.

Complete step-by-step solution:
We know that the given function is,
f(x)=(x33)3xf\left( x \right)=\left( \dfrac{{{x}^{3}}}{3} \right)-3x on the interval [3,3]\left[ -3,3 \right].
We can now see that,
f(x)\Rightarrow f\left( x \right) is a continuous function.
f(3)=0=f(3)\Rightarrow f\left( -3 \right)=0=f\left( 3 \right)
When we apply the given values of a and b in f(x)f\left( x \right), we get 0.
Thus, the conditions of Rolle’s theorem are satisfied with a = -3 and b = 3 and so there is a x(a,b)x\in \left( a,b \right)which satisfies f(x)=0f'\left( x \right)=0.
We can now find f(x)f'\left( x \right)by differentiating f(x)f\left( x \right).
f(x)=x23\Rightarrow f'\left( x \right)={{x}^{2}}-3
We can now substitute ±3\pm \sqrt{3} in f(x)f'\left( x \right), to get the condition to be satisfied.

& \Rightarrow f'\left( x \right)={{\left( \sqrt{3} \right)}^{2}}-3=3-3=0 \\\ & \Rightarrow f'\left( x \right)={{\left( -\sqrt{3} \right)}^{2}}-3=3-3=0 \\\ \end{aligned}$$ We can now see that the above derivative vanishes at two points $$\pm \sqrt{3}$$ in the interval $$\left( -3,3 \right)$$. **Therefore, Rolle’s theorem is satisfied for the given function $$f\left( x \right)=\left( \dfrac{{{x}^{3}}}{3} \right)-3x$$ on the interval $$\left[ -3,3 \right]$$.** **Note:** We should remember that Rolle’s theorem says that there is a $$x\in \left( a,b \right)$$ where $$f'\left( x \right)$$ will vanish, not that there will necessarily be only one. We should also know that the given function should be a continuous differentiable function, which can be further analysed for the conditions in Rolle's theorem.