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Question

Question: How to find the derivative of \(Sin3{x^2}\) ?...

How to find the derivative of Sin3x2Sin3{x^2} ?

Explanation

Solution

Hint : Derivative is the process of finding small changes in function with respect to the given variable. There are basic formulae with which we can find derivatives like ddxSinx=Cosx\dfrac{d}{{dx}}\operatorname{Sin} x = \operatorname{Cos} x .
But, in a given problem there is an implicit function. These types of problems can be solved using chain derivative methods.

Complete step-by-step answer :
Given function : y=3x2y = 3{x^2}
We can look at the function as Siny=Sin3x2Siny = Sin3{x^2}
Where, y=3x2y = 3{x^2}
ddy(Sin3x2)=Cos3x2×ddx(3x2)\Rightarrow \dfrac{d}{{dy}}\left( {Sin3{x^2}} \right) = Cos3{x^2} \times \dfrac{d}{{dx}}(3{x^2})
Here as stated above y=3x2y = 3{x^2}
ddy(Sin3x2)=Cos3x2×ddx(3x2)\Rightarrow \dfrac{d}{{dy}}\left( {Sin3{x^2}} \right) = Cos3{x^2} \times \dfrac{d}{{dx}}(3{x^2}) ………. (1)\left( 1 \right)
As we know, ddx(ax2)=2ax \Rightarrow \dfrac{d}{{dx}}(a{x^2}) = 2ax …… aa is constant
ddy(Sin3x2)=Cos3x2×2×3×x\Rightarrow \dfrac{d}{{dy}}\left( {Sin3{x^2}} \right) = Cos3{x^2} \times 2 \times 3 \times x
ddy(Sin3x2)=6xCos(3x2)\Rightarrow \dfrac{d}{{dy}}\left( {Sin3{x^2}} \right) = {\text{6}}xCos(3{x^2})
Answer is 6xCos(3x2) \to {\text{6}}xCos(3{x^2})
So, the correct answer is “ 6xCos(3x2) \to {\text{6}}xCos(3{x^2}) ”.

Note : This method can be applied on a range of problems involving implicit functions. Also, there can be multiple implicit functions in a given function for example Cos(3sin(4x3))Cos(3sin(4{x^3})) . In such cases the derivatives of the implicit functions are kept on multiplying until dxdx\dfrac{{dx}}{{dx}}i.e. 11 .
Assuming the inner function f(y)f\left( y \right) and taking derivatives with respect to helps in avoiding mistakes.