Question

How much would a $W$ kg man weigh on the moon in terms of gravitational units?
(A) $\dfrac{W}{6}$ kg-wt
(B) $6w\,$ kg-wt
(C) $W$ kg-wt
(D) zero

Answer 1

The moon’s surface gravity is about $1/6$ th as powerful or about $1.6$ meters per second. The Moon’s surface gravity is weaker because it is far less massive than earth. A body’s surface gravity is proportional to its mass, but inversely proportional to the square of its radius.

Complete answer:
The Earth’s Moon has considerably less mass than the earth itself. Not only is the moon smaller than the earth, but it is only about $60$ percent as dense as earth. Thus, the gravitational attraction on the moon is much less than it is here on earth, and a person weighs less on the moon. $1.62m/{s^2}$ earth has a greater gravitational pull than the moon simply because the earth is more massive. That’s why the moon is not pulled out earth’s orbit by the gravity of larger planets or by the sun. the greater an object's mass, the more gravitational force it exerts.
The gravity on the moon is $1/6$ th that of the earth. A man weighing $100kg$ on earth,
Would weigh $\dfrac{{100}}{6}$ i.e. $16.66kg$ on the moon.
Hence, a man with a $W$ kg would weigh $\dfrac{W}{6}$ kg-wt on the moon.

So, the correct answer is “Option A”.

Note:
When objects which have mass are attracted to each other, then the force between them is known as Gravitational force.
Gravity is all around us. It keeps the planet in our Solar System, for example, in orbit around the sun.
The moon stays in orbit around the earth also because of gravity.