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Question

Chemistry Question on Solutions

How much oxygen is dissolved in 100mL100\, mL water at 298K298\, K if partial pressure of oxygen is 0.5atm0.5\, atm and KH=1.4×103mol/L/atmK_H = 1.4 \times 10^{-3}\, mol/L/atm ?

A

22.4mg22.4 \,mg

B

22.4g22.4\, g

C

2.24g2.24 \,g

D

2.24mg2.24 \,mg

Answer

2.24mg2.24 \,mg

Explanation

Solution

According to Henry?? law, s=KH×ps = K_H \times p, where s is concentration of O2O_2 dissolved. s=1.4×103×0.5s = 1.4 \times 10^{-3} \times 0.5 =0.7×103mol/L= 0.7 \times 10^{-3}\,mol/L s=nVs = \frac{n}{V} or n=0.7×103×0.1n = 0.7 \times 10^{-3} \times 0.1 =0.7×104mol= 0.7 \times 10^{-4}\,mol n=wMn = \frac{w}{M} or w=n×Mw = n \times M =0.7×104×32= 0.7 \times 10^{-4} \times 32 =22.4×104g = 22.4 \times 10^{-4}\, g or 2.24mg2.24\, mg