Question

How much of NaOH is required to neutralise 1500 of 0.1 N HCl (At. wt. of Na =23).

• A. 4 g
• B. 6 g
• C. 40 g
• D. 60 g

Answer 1

Answer: (B)

6 g

Answer 2

1500 of 0.1 N HCl have number of gm equivalence

$= \frac { N _ { 1 } \times V _ { 1 } } { 1000 } = \frac { 1500 \times 0.1 } { 1000 } = 0.15$

equivalent of NaOH