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Question: How much momentum does an \(\dfrac{1}{2}kg\) object moving at \(64m{\sec ^{ - 1}}\) have?...

How much momentum does an 12kg\dfrac{1}{2}kg object moving at 64msec⁡−164m{\sec ^{ - 1}} have?

Explanation

Solution

Momentum is defined as the mass content of motion; momentum is the product of the mass of a body, and its velocity. A body that has some mass and is moving possesses momentum. The momentum directly depends upon the mass of the body

Complete step by step answer:
As we know momentum is defined as the mass content of motion this simply means how much mass is set in the motion. The momentum of a body is expressed by p and is a product of the mass and velocity of the body
Mathematically,
p=m×vp = m \times v
Here in this question, we are given a body of mass12kg\dfrac{1}{2}kgthat is moving at a velocity of 64msec⁡−164m{\sec ^{ - 1}}and we need to calculate the momentum of the body
Substituting the values of mass and velocity in the equation we get
p=64×12p = 64 \times \dfrac{1}{2}
p=32kgmsec⁡−1p = 32kgm{\sec ^{ - 1}}
Final answer:
A body of mass 12kg\dfrac{1}{2}kg moving at 64msec⁡−164m{\sec ^{ - 1}} will have momentum equal to 32kgmsec⁡−132kgm{\sec ^{ - 1}}

Note:
The momentum of the body is directly proportional to the mass and velocity of the body
When two bodies collide there is always conservation of momentum.
According to the law of conservation of momentum “during collisions of two or more bodies after the collision happens, the individual momentums of bodies may increase or decrease but the total momentum before the collision will always be equal to the total momentum after the collision.”
The law of conservation of momentum is based on Newton’s third law because the law of conservation of momentum can be derived from the law of action and reaction