Question
Question: How much load of specific gravity \[11\] should be added to a piece of cork of specific gravity \(0....
How much load of specific gravity 11 should be added to a piece of cork of specific gravity 0.2 weighing 10g so that it may just float on water?
(A) 4.4g
(B) 44g
(C) 440g
(D) 2.2g
Solution
Specific Gravity is defined as the ratio of density of a given object to the density of water. For the cork to just float on water, it has to be in complete vertical equilibrium, that is the buoyant force has to be equal to the total weight.
Complete step by step answer:
We know that specific gravity is the ratio between the density of an object and density of water (ρ). So to calculate density of load (ρ1),
Specific Gravity=ρρ1
⇒11=ρρ1
Since, ρ=1g/cc
⇒ρ1=11g/cc
Similarly the density of cork (ρ2) can be calculated and,
ρ2=0.2g/cc
Mass of cork, m2=10g
So, the volume of cork, V2=ρ2m2
⇒V2=0.210
⇒V2=50cm3
Let the volume of load which is to be added be V1, then in order to attain equilibrium, buoyant force (FB) has to be equal to the sum of weight of load and weight of cork(W2), that is
⇒FB=W1+W2
Since the cork and load displace V1+V2 volume of water,
⇒(V1+V2)ρg=mg+V1ρ1g
⇒V1+V2=m+V1ρ1
⇒[ρ=1g/cc]
⇒V2−m=V1ρ1−V1
⇒V2−m=V1(ρ1−1)
⇒V1=ρ1−1V2−m
⇒V1=11−150−10
⇒V1=1040
⇒V1=4cm3
To calculate mass of the load to be added, m1=ρ1V1
⇒m1=11×4
⇒m1=44g
Therefore option B is correct.
Note: Buoyant force is an upward force exerted by the water displaced by the object. If the buoyant force is greater than or equal to the weight of the object, the object floats. If the buoyant force is less than the weight of the object, it sinks.