Question

How much energy would be absorbed as heat by 75g of iron when heated from 295K to 301K? c=.46

Answer 1

Before solving this question, we have to first know the formula to find Heat Energy. It is represented by q. The formula is: $q=\,mc\vartriangle T$. Now we can put all the values in the formula and can easily find the required energy.

Complete answer:
The temperature of the substance will change by a certain amount when heat energy is added to it. Every material has a different relation between heat energy and temperature and the value that describes the relation of it is the specific heat.
$q=\,mc\vartriangle T$
In this, q is the energy
m is the mass
c is the specific heat capacity
$\vartriangle T$is the change in temperature ($\vartriangle T={{T}_{final}}-{{T}_{initial}}$)
The values that are given in this question are-
Mass = 75g
c = .46
${{T}_{final}}$= 301 K
${{T}_{initial}}$= 295 K
To find $\vartriangle T$, we have to subtract the Initial temperature from the final temperature.
$\vartriangle T={{T}_{final}}-{{T}_{initial}}$
$\vartriangle T$= 301 K – 295 K = 6 K
The only value that is unknown to us-
q =?
so, $q=\,mc\vartriangle T$
Now, we will put the values of the quantities in the formula:
$q=\,75\,\times \,.46\,\times \,6$
$q=\,207\,Joules$
So, The amount of Heat energy required is 207 J.

Note:
The specific heat capacity is the amount of heat required to raise the temperature of the substance by 1${}^\circ C$.
The units of all the quantities in the Formula are-
Heat Energy is (Joules, J)
Mass of a substance is (Kilogram, Kg)
Specific heat is (J/Kg.K)
Temperature is ( Kelvins)