Question

How much current should be passed through acidified water for 100 s to liberate 0.224 litre of $H_{2}$

• A. 22.4 A
• B. $19.3A$
• C. 9.65 A
• D. 1 A

Answer 1

Answer: (B)

$19.3A$

Answer 2

22.4 litre H₂ = 1 mole H₂ = N molecules of H₂

= 2N atom of H

So charge required to liberate 22.4 litre of H₂ = 2Ne = 2F Hence charge required to liberate 0.224 litre of H₂ $= \frac{2F}{22.4} \times 0.224 = \frac{2F}{100} = 2 \times 965C$

So current $i = \frac{Q}{t} = \frac{2 \times 965}{100} = 19.3amp$