Question

How much copper can be obtained from 100 g of copper sulphate $(\text{CuSO}_4)$?

Answer 1

1 mole of $(\text{CuSO}_4)$ contains 1 mole of copper.
Molar mass of $(\text{CuSO}_4)$ = (63.5) + (32.00) + 4(16.00)
= 63.5 + 32.00 + 64.00
= 159.5 g
159.5 g of $(\text{CuSO}_4)$ contains 63.5 g of copper.
⇒ 100 g of $(\text{CuSO}_4)$ will contain $\frac{63.5 × 100\, \text{g} }{ 159.5}$ of copper.
Amount of copper that can be obtained from 100 g $(\text{CuSO}_4)$ $= \frac{63.5 × 100\, \text{g} }{ 159.5}$
= 39.81 g