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Question: How much concentrated solution do you measure out and how much water do you need to add to make \( 5...

How much concentrated solution do you measure out and how much water do you need to add to make 500ml500{\text{ml}} 0.1MHCl0.1{\text{M}}HCl from 2MHCl2{\text{M}}HCl ?

Explanation

Solution

Molar concentration is a measure of the concentration of a chemical substance, in terms of amount of the substance per unit volume of the solution. The SI unit of molarity is moldm - 3{\text{mold}}{{\text{m}}^{{\text{ - 3}}}} . However, when a solution has a concentration of 1mol/L1{\text{mol/L}} it is said to be a 1 molar solution and is represented as 1M1M of the particular chemical substance that forms the solution.

Formulas used: We will be using the formula to find the number of moles of a substance provided we have the molarity of its solution, n=MVn = MV where nn is the number of moles of the substance, MM is the molarity of the substance, and VV is the volume of the solution in litres.

Complete Step by Step answer
We know that the molarity is the measure of concentration of a chemical substance in its solution. A substance that has molarity 1M1M is nothing but that one mole of the chemical substance is dissolved in 1 litre of the solvent to form a solution with concentration 1M1M . Thus, from the definition of molarity we can infer that,
1M=1mole1L1M = \frac{{1{\text{mole}}}}{{1L}}
From the problem we can infer that 0.1M0.1M solution of HClHCl is made with 500ml500{\text{ml}} volume of water, we need to find the amount of HClHCl that should be added to the 2M2M concentrated solution. This means that the number of moles of the chemical substance remains unchanged. Thus,
M1V1=n=M2V2{M_1}{V_1} = n = {M_2}{V_2}
M1V1=M2V2{M_1}{V_1} = {M_2}{V_2}
Substituting the known values of M1=2M,V1=x,M2=0.1M,V2=500mL{M_1} = 2{\text{M}},{V_1} = x,{M_2} = 0.1{\text{M}},{V_2} = 500{\text{mL}} we get,
(2.0M)×(x)=(0.1)×500mL\left( {2.0{\text{M}}} \right) \times \left( x \right) = \left( {0.1} \right) \times 500{\text{mL}}
Solving for V1=x{V_1} = x ,
x=0.1×5002.0x = \frac{{0.1 \times 500}}{{2.0}}
x=502=25mL\Rightarrow x = \frac{{50}}{2} = 25{\text{mL}}
Thus, to make a 2M2{\text{M}} concentrated solution we have to dilute 25mL25{\text{mL}} in 475mL475{\text{mL}} of water.

Note
In a laboratory the process can be done using a volumetric flask to ensure the total volume is 500mL500{\text{mL}} . Also make sure that the water is not poured into the acid, this causes an exothermic explosive reaction. Concentration can also be expressed as molality, i.e. the number of moles of solute present in 1Kg of solvent.