Question
Question: How many water molecules are present in \( 54 \) gram of water?...
How many water molecules are present in 54 gram of water?
Solution
To solve this question first we will calculate the number of moles of H2O present. After that we will multiply the number of moles with Avogadro’s number by which we will get the number of molecules.
numberofmolesofH2O=molecularweightofH2OWeightofthegivensample .
Complete answer:
To solve this question we have to know about the concept of moles and molecular weight. Moles are the basic unit of the SI, i.e. International System of Units. It has exactly 6.022×1023 particles which can be atoms, molecules, ions or electrons. Molecular weight is the total mass of the atoms present in the molecule.
As we know that one mole contains 6.022×1023 molecules. Moreover we also know that one mole of water weighs 18gm as the molecular mass of water is 18 . Thus, 18gm of water has 6.022×1023 molecules of water.
It is given that mass of water is 54gm
Now we know that one mole of water weighs 18gm , so according to the question, moles of given of 54gm water is:
numberofmolesofH2O=molecularweightofH2OWeightofthegivensample
⇒numberofmoles=1854
⇒numberofmoles=3
As these are in moles and we have to find the number of molecules of water and we also know that one mole has 6.022×1023 molecules. So we will multiple the calculated amounts with it then we get:
numberofmolecules=numberofmoles×6.022×1023
⇒numberofmolecules=3×6.022×1023
⇒numberofmolecules=1.8066×1024
⇒numberofmolecules≈1.8×1024
Thus there are 1.8×1024 molecules in 54 grams of water.
Note:
In this question we can also use that one mole of water has 18.0152gm . In the above solution, we have taken a round off of this value. So the number of moles of water we have will be:
⇒numberofmoles=18.015254
⇒numberofmoles=2.997
Thus the number of molecules will be:
⇒numberofmolecules=2.997×6.022×1023
⇒numberofmolecules=1.805×1024
⇒numberofmolecules≈1.8×1024
Thus, you can find the answer in this way too.