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Question

Data Interpretation & Logical Reasoning (DILR) Question on Binary logic

How many times are the hands of a clock at right angle in a day?

A

22

B

33

C

44

D

21

Answer

44

Explanation

Solution

The minute hand covers 360360\degree in an hour and 66\degree in a minute.

The hour hand covers 30° in an hour and 0.50.5\degree in a minute.

Calculation:

Starting from midnight i.e. 12 o clock at the midnight, the first time the difference between the two hands would be 9090\degree is:

6x=0.5x+906x=0.5x+90\degree (x is the number of minutes)

5.5x=905.5x=90\degree

x=18011x=\frac{180}{11} minutes
The next time the difference between the two hands would be 9090\degree is when the minute hand would have moved 180180\degree away from the hour hand or the difference between both hands would have been 270270\degree.

6x=0.5x+2706x=0.5x+270

5.5x=2705.5x=270

x=54011x=\frac{540}{11} minutes

Thus, the difference between two consecutive moments where both hands forms a right angle is:

5401118011=36011\frac{540}{11}-\frac{180}{11}=\frac{360}{11} minutes

Thus, the two hands form a right angle after every 36011\frac{360}{11} minutes.

Total number of minutes in a day =24×60=1440=24\times60=1440 minutes.
Number of times the two hands will form a right angle in a day =1440(36011)=\frac{1440}{(\frac{360}{11})}

(1440×11)360\frac{(1440\times11)}{360}

4×11=444\times11=44
The correct option is (C):44