Question

How many three member ring(s) is/are formed in$Cr{O_5}$?

Answer 1

Hint : We must remember that the member rings is the term that means the cyclic structure that is formed by a group of atoms and the bonds between them.

Complete step by step solution :
Let's first begin with explaining more about the member ring. Member rings are a vague term that we use while talking about the cyclic structure that is formed by a group of atoms and the bonds between them.
If a structure has no rings present in it then we call it an acyclic or open-chain compound. If the ring is a simple one, then we call it a monocycle and if it's relatively complex then we refer to it as a polycycle.
Another classification is the homocyclic and heterocyclic ring classification. A ring is called homocyclic if all the atoms are of the same element. A special class of homocyclic compounds are the carbocycle where all the elements are carbon. A heterocyclic has different elements in its ring.
In $Cr{O_5}$the Cr atom is having six valence electrons for bond formation and hence, forms the structure that is shown below. $Cr{O_5}$has five oxygen (O) atoms. Four oxygen atoms are involved in peroxide bonds. So $Cr{O_5}$have two linkages.

Looking at this structure we can see two distinct rings which are three membered.
So, the $Cr{O_5}$is having 2 three member rings.

Note : We must remember that when we calculate the oxidation state of a central atom. The calculated oxidation state of the central atom is greater than the maximum oxidation state of that atom. Then we can confirm there’s peroxide linkages present.