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Question: How many \({\text{Fe}}\) atoms are contained in \(787{\text{ g}}\) of \({\text{Fe}}\)?...

How many Fe{\text{Fe}} atoms are contained in 787 g787{\text{ g}} of Fe{\text{Fe}}?

Explanation

Solution

We are given the mass of a substance i.e. Fe{\text{Fe}}. To solve this first calculate the number of moles of Fe{\text{Fe}} in 787 g787{\text{ g}} of Fe{\text{Fe}}. We know that 1 mol{\text{1 mol}} of any substance contains 6.022×10236.022 \times {10^{23}} atoms. 6.022×10236.022 \times {10^{23}} is Avogadro's number. Then calculate the number of atoms of Fe{\text{Fe}} in 787 g787{\text{ g}} of Fe{\text{Fe}}.

Complete answer:
We are given the mass of a substance i.e. Fe{\text{Fe}}. The number of moles of any substance is the ratio of mass (in grams) to the molar mass (in gram per mol).
Thus, the equation to calculate the number of moles is as follows:
Number of moles(mol)=Mass(g)Molar mass(g/mol){\text{Number of moles}}\left( {{\text{mol}}} \right) = \dfrac{{{\text{Mass}}\left( {\text{g}} \right)}}{{{\text{Molar mass}}\left( {{\text{g/mol}}} \right)}}
Substitute 787 g787{\text{ g}} for the mass, 55.84 g/mol55.84{\text{ g/mol}} for the molar mass. Thus,
Number of moles of Fe{\text{Fe}} =787 g55.84 g/mol = \dfrac{{787{\text{ g}}}}{{55.84{\text{ g/mol}}}}
Number of moles of Fe{\text{Fe}} =14.09 mol = 14.09{\text{ mol}}
Thus, moles of Fe{\text{Fe}} in 787 g787{\text{ g}} of Fe{\text{Fe}} is 14.09 mol14.09{\text{ mol}}.
We know that the amount of substance having exactly the same number of atoms as are present in 12 g12{\text{ g}} of C12{{\text{C}}^{{\text{12}}}} is known as mole. Moles is the ratio of the mass of substance in g to the molar mass of the substance in g/mol{\text{g/mol}}. 1 mol{\text{1 mol}} of any substance contains 6.022×10236.022 \times {10^{23}} atoms. 6.022×10236.022 \times {10^{23}} is Avogadro's number.
We know that 1 mol{\text{1 mol}} of any substance contains 6.022×10236.022 \times {10^{23}} atoms. We have 14.09 mol14.09{\text{ mol}} of Fe{\text{Fe}}. Thus,
Number of Fe{\text{Fe}} atoms =14.09 mol×6.022×1023 atoms1 mol = 14.09{\text{ mol}} \times \dfrac{{6.022 \times {{10}^{23}}{\text{ atoms}}}}{{1{\text{ mol}}}}
Number of Fe{\text{Fe}} atoms =84.84×1023 atoms = 84.84 \times {10^{23}}{\text{ atoms}}
Thus, 787 g787{\text{ g}} of Fe{\text{Fe}} contains 84.84×102384.84 \times {10^{23}} atoms of Fe{\text{Fe}}.

Note: Amount of substance having exactly the same number of atoms as are present in 12 grams of C12{{\text{C}}^{{\text{12}}}} is known as mole. The number of molecules in one mole of a compound is Avogadro’s number. The number 6.022×10236.022 \times {10^{23}} is known as Avogadro’s number.