Question
Question: How many \({\text{Fe}}\) atoms are contained in \(787{\text{ g}}\) of \({\text{Fe}}\)?...
How many Fe atoms are contained in 787 g of Fe?
Solution
We are given the mass of a substance i.e. Fe. To solve this first calculate the number of moles of Fe in 787 g of Fe. We know that 1 mol of any substance contains 6.022×1023 atoms. 6.022×1023 is Avogadro's number. Then calculate the number of atoms of Fe in 787 g of Fe.
Complete answer:
We are given the mass of a substance i.e. Fe. The number of moles of any substance is the ratio of mass (in grams) to the molar mass (in gram per mol).
Thus, the equation to calculate the number of moles is as follows:
Number of moles(mol)=Molar mass(g/mol)Mass(g)
Substitute 787 g for the mass, 55.84 g/mol for the molar mass. Thus,
Number of moles of Fe =55.84 g/mol787 g
Number of moles of Fe =14.09 mol
Thus, moles of Fe in 787 g of Fe is 14.09 mol.
We know that the amount of substance having exactly the same number of atoms as are present in 12 g of C12 is known as mole. Moles is the ratio of the mass of substance in g to the molar mass of the substance in g/mol. 1 mol of any substance contains 6.022×1023 atoms. 6.022×1023 is Avogadro's number.
We know that 1 mol of any substance contains 6.022×1023 atoms. We have 14.09 mol of Fe. Thus,
Number of Fe atoms =14.09 mol×1 mol6.022×1023 atoms
Number of Fe atoms =84.84×1023 atoms
Thus, 787 g of Fe contains 84.84×1023 atoms of Fe.
Note: Amount of substance having exactly the same number of atoms as are present in 12 grams of C12 is known as mole. The number of molecules in one mole of a compound is Avogadro’s number. The number 6.022×1023 is known as Avogadro’s number.