Question

How many stereoisomers of $\text{2 - chloro - 3 - methylbutane}$ exist?

Answer 1

To know the existence of stereoisomers of $\text{2 - chloro - 3 - methylbutane}$, we should go through the configuration of $\text{2 - chloro - 3 - methylbutane}$. And then on the basis of configuration, we can conclude the stereoisomers.

Complete step by step solution:
Simply put, there are two configurations per stereo-centre on a compound with all $s{p^3}\;carbons;\;R\,or\;S$ . So, we rack up stereoisomers according to $2 \cdot 2 \cdot 2 \cdot [...] \cdot 2 = {2^n}$ where $n$ is the number of stereo-centres.
Also, although meso isomers could reduce the number of stereoisomers, there are none here because clearly, $Cl \ne C{H_3}$ , i.e. there is no plane of symmetry. Therefore, we can ignore meso isomers.
So, there are a total ${2^2}$ or 4 stereoisomers of $\text{2 - chloro - 3 - methylbutane}$ exist in nature.

Note:
Stereoisomers are isomers that have the same composition (that is, the same parts) but that differ in the orientation of those parts in space. There are two kinds of stereoisomers: enantiomers and diastereomers. Enantiomers are mirror images, like one’s hands, and diastereomers.